
Written and maintained by the PhDino author · Last reviewed 21 September 2026 · Checked against 2 independent reference calculations · how PhDino checks its numbers
Related standards: NEC
Choosing a conductor size large enough to keep voltage drop within an allowed percentage over a given run.
Every conductor has some resistance, so current flowing through it produces a voltage drop proportional to current, resistance, and run length. Undersized wire for a long run can drop enough voltage that equipment at the far end receives noticeably less than nominal voltage — motors run hot and inefficient, and electronics may malfunction. The NEC recommends keeping voltage drop within about 3% for branch circuits (5% combined feeder+branch).
This calculator uses the circular-mil method: it computes the minimum conductor area (in circular mils) that keeps voltage drop under the allowed percentage, then matches that up to the next standard wire size.
Required area (circular mils) = (2 × L × I × ρ) / V_allowed V_allowed = (%Drop / 100) × System Voltage
Use this when a long run is the problem: it finds the smallest copper conductor that keeps voltage drop within the percentage you allow, then rounds up to the next standard size. Over a few hundred feet, voltage drop rather than heating is what decides the wire size, and it is the check people forget.
It does one job only. It does not check ampacity, the current a conductor can carry without overheating, and on short runs ampacity usually asks for a larger wire than voltage drop does. Size for both and use the larger of the two results.
A 120 V, 20 A well pump sits 200 ft from the panel. The most drop you will accept is 3%. A 20 A circuit is normally wired in #12 copper. Is that enough for this distance?
| You enter | Value |
|---|---|
| Current | 20 A |
| Allowed V Drop | 3 % |
| Cable Length | 200 ft |
| System Voltage | 120 V |
| The calculator returns | Value |
|---|---|
| Required Area | 23.05 kcmil |
| Next Standard Size | 26.24 kcmil |
| Actual V Drop | 2.63 % |
Worked by hand:
This run needs #6 AWG for voltage drop, three sizes larger than the #12 that ampacity alone would suggest for a 20 A circuit. That jump is typical of long runs and is the reason the check matters. Confirm that #6 also satisfies the ampacity and terminal requirements for the breaker you use, and treat the larger of the two answers as the wire size.
A conductor has to satisfy two independent limits. Ampacity is a thermal limit, set by how much current the insulation can stand in the installed conditions; voltage drop is a performance limit, set by how much voltage the load can afford to lose. Short, heavily loaded runs are governed by ampacity, and long, lightly loaded ones by voltage drop. The wire you install is the larger of the two.
For both, and you install the larger result. Ampacity keeps the insulation from overheating; voltage drop keeps the load supplied properly. Which one governs depends on the length of the run and the size of the load.
A kcmil is a thousand circular mils, the unit of conductor cross-section used for large wire. #6 AWG is 26.24 kcmil. Conductors up to 4/0 are usually named by AWG number and larger ones directly in kcmil.
Yes, if you scale the area up by about 1.6 and use connectors rated for aluminum. Many feeders are aluminum for cost, but each termination matters more than with copper.
Yes. A balanced three-phase circuit loses less voltage per conductor, so it needs about 87 percent of the single-phase area for the same current and drop. This calculator gives the single-phase result.
The calculation of the temperature rise and load capability of cable systems Neher, J. H. & McGrath, M. H. (1957), AIEE Transactions. The paper behind the standard method for working out how much current a cable can carry before it overheats, which is where published ampacity tables come from.
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The Art of Electronics by Paul Horowitz & Winfield Hill — The standard practical reference on circuit design, from Ohm’s law to real amplifiers. (Bookshop.org UK, UK delivery only)
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